�� D4-02DA 2-Channel Analog Output ���������������������� ����������������������� ����������������������������� ������������������ ����������������������������� 11–2 D4-02DA 2-Channel Analog Output Module Specifications ANALOG OUTPUT TB 24V CH1 CH2 The D4–02DA 2-Channel Analog Output DATA 1 16 256 module provides several features and 2 32 512 benefits. 64 1024 4 8 128 2048 D4–02DA � It provides two channels of voltage DISPLAY CH or current outputs. � Analog outputs are optically isolated +I from PLC logic components. –I � The module has a removable CH1 terminal block, so the module can be +V easily removed or changed without –V disconnecting the wiring. +I � Both analog outputs may be set in one CPU scan. –I CH2 +V –V 0–10VDC 1–5VDC 4mA–20mA 24VDC 0.3A CLASS 2 D4–02DA Analog Output The D4–02DA Analog Output requires 32 discrete output points from the CPU. The Configuration module can be installed in any slot of a DL405 system, including remote bases. The Requirements limitations on the number of analog modules are: � For local and expansion systems, the available power budget and discrete I/O points. � For remote I/O systems, the available power budget and number of remote I/O points. Check the user manual for your particular model of CPU for more information regarding power budget and number of local or remote I/O points. D4–02DA 2-Ch. Analog Output D4–02DA 2-Ch. Analog Output 11–3 D4-02DA 2-Channel Analog Output The following table provides the specifications for the D4–02DA Analog Output Module. Review these specifications to ensure the module meets your application requirements. Output Number of Channels 2 (independent) Specifications Output Ranges 0–10V, 1–5V, 4–20 mA Resolution 12 bit (1 in 4096) Output Type Single ended Output Impedance 0.5Ω maximum, voltage output Output Current 5 mA maximum, voltage output Load Impedance 550Ω max., 5.0Ω min.,current output, 2KΩ minimum, voltage output Linearity �0.1% maximum Accuracy vs. Temperature �70 ppm / �C maximum Maximum Inaccuracy �0.2% maximum at 25� C Conversion Method Integration Conversion Time Start of scan, 30µS + one scan General Module PLC Update Rate 1 or 2 channels per scan Specifications Digital Output Points Required 32 (Y) output points 12 binary data bits per channel (24 bits total with 8 unused bits) Power Budget Requirement 250 mA (from base) External Power Supply 24VDC, �10%, 300 mA, class 2 Operating Temperature 0 to 60�C (32 to 140°F) Storage Temperature –20 to 70�C (–4 to 158°F) Relative Humidity 5 to 95% (non-condensing) Environmental air No corrosive gases permitted Vibration MIL STD 810C 514.2 Shock MIL STD 810C 516.2 Insulation Resistance 10 M�, 500 VDC Noise Immunity NEMA ICS3–304 11–4 D4-02DA 2-Channel Analog Output Connecting the Field Wiring Wiring Guidelines Your company may have guidelines for wiring and cable installation. If so, you should check those before you begin the installation. Here are some general things to consider. � Use the shortest wiring route whenever possible. � Use shielded wiring and ground the shield at the module or the power supply return (0V). Do not ground the shield at both the module and the transducer. � Do not run the signal wiring next to large motors, high current switches, or transformers. This may cause noise problems. � Route the wiring through an approved cable housing to minimize the risk of accidental damage. Check local and national codes to choose the correct method for your application. User Power The D4–02DA requires a separate power supply. The DL430/440/450 CPUs, Supply D4–RS Remote I/O Controller, and D4–EX Expansion Units have built-in 24 VDC power supplies that provide up to 400mA of current. If you only have one analog Requirements module, you can use this power source instead of a separate supply. If you have more than one analog module, or you would rather use a separate supply, choose one that meets the following requirements: 24 VDC �10%, Class 2, 300mA (per module). Load Each channel can be wired independently for voltage or current. Requirements � Current loads must have an impedance between 5 and 500 ohms. � Voltage loads must have an impedance greater than 2K ohms. Using the Since the module provides a 0–10V signal on the voltage outputs, you have to use 1–5 VDC Range the current outputs and a precision resistor to generate the 1–5V signal. With a 250 ohm precision resistor across the current outputs, the module converts the current signals to voltage for you (4mA x 250 ohms = 1V, 20mA x 250 ohms = 5V). The transducer should be connected in parallel with the precision resistor and the parallel equivalent resistance should be approximately 250 ohms (�0.1%). Field devices that have impedances of greater than 250K ohms can be used with less than 0.1% additional inaccuracy. See the following diagram. Module (internal equivalent circuit) Only one channel shown Precision Load resistance resistor (DC input impedance) +I + R R p 1–5V L –I – +V Not Used –V R R p L � 250� 0V R � R p L R = value of external precision resistor p R = load impedance L D4–02DA 2-Ch. Analog Output D4–02DA 2-Ch. Analog Output 11–5 D4-02DA 2-Channel Analog Output Wiring Diagram The D4–02DA module has a removable connector to make wiring easier. Simply remove the retaining screws and gently pull the connector from the module. NOTE 1: Shields should be connected to the 0V terminal of the module or power supply. NOTE 2: Unused voltage and current outputs should remain open (no connections). ANALOG OUTPUT TB 24V CH1 CH2 DATA 1 16 256 2 32 512 4 64 1024 CH1 8 128 2048 See NOTE 1 V+ D4–02DA D/A Channel 1 is wired for current output DISPLAY +I CH User Load –I +I Shielded 5 to 550 ohms +V CH2 –I V+ CH1 –V D/A +V See NOTE 2 +I –V –I +I Channel 2 is wired for voltage output –I +V User Load CH2 –V +V 2K ohms or greater Shielded –V NC 24V 0–10VDC 1–5VDC 4mA–20mA 0V + – User Supply 24VDC 0.3A 21.6 – 26.4 VDC CLASS 2 OV D4–02DA 11–6 D4-02DA 2-Channel Analog Output Module Operation DL430 Special Even though the module can be placed in any slot, it is important to examine the Requirements configuration if you’re using a DL430 CPU. As you’ll see in the section on writing the program, you use V-memory locations to extract the analog data. As shown in the following diagram, if you place the module so that the input points do not start on a V-memory boundary, the instructions can’t access the data. D4–02DA Correct! 8pt 8pt 32pt 16pt 8pt 8pt Output Output Output Output Input Input Slot 0 Slot 1 Slot 2 Slot 3 Slot 4 Slot 5 Y0 Y10 Y60 Y20 – – – – Y7 Y17 Y77 Y57 V40500 V40503 Data is correctly entered so input points start on a V-memory boundary address. V40502 – V40501 MSB V40502 LSB MSB LSB V40501 Y Y Y Y Y Y Y Y 5 5 4 4 3 3 2 2 7 0 7 0 7 0 7 0 D4–02DA Wrong! 8pt 32pt 8pt 16pt 32pt 8pt Output Output Output Output Input Input Slot 0 Slot 1 Slot 2 Slot 3 Slot 4 Slot 5 Y0 Y10 Y60 Y50 – – – – Y7 Y47 Y77 Y57 Data is split over three locations, so instructions cannot access data from a DL430. V40502 V40501 V40500 MSB LSB MSB LSB MSB LSB Y Y Y Y Y Y Y Y Y Y Y Y 1 1 7 0 5 4 4 3 2 2 5 3 7 0 0 7 0 0 7 0 7 7 D4–02DA 2-Ch. Analog Output D4–02DA 2-Ch. Analog Output 11–7 D4-02DA 2-Channel Analog Output Before you begin writing the control program, it is important to take a few minutes to understand how the module processes and represents the analog signals. Channel Scanning The D4–02DA module updates both channels in the same scan. The control Sequence program updates the two channels of this module independent of each other and each channel does not have to be refreshed on every scan. Scan Read inputs Channel 1 Scan N Channel 2 Execute Application Program Calculate the data Channel 1 Scan N+1 Channel 2 Channel 1 Scan N+2 Channel 2 Write data Channel 1 Scan N+3 Channel 2 Channel 1 Scan N+4 Channel 2 Write to outputs 11–8 D4-02DA 2-Channel Analog Output Output Bit You may recall the D4–02DA module requires 32 discrete output points. These 32 Assignments points provide the digital representation of the analog signals. Since all output points are automatically mapped into V-memory, it is very easy to determine the location of the data word that will be assigned to the module. D4–02DA 8pt 8pt 32pt 16pt 16pt 16pt Output Output Output Output Input Input Y0 Y10 Y20 Y60 – – – – Y7 Y17 Y57 Y77 V40500 V40503 V40502 V40501 MSB LSB MSB LSB Bit 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 Bit 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 Y Y Y Y Y Y Y Y 5 5 4 4 3 3 2 2 7 0 7 0 7 0 7 0 Within these two word locations, the individual bits represent specific information about the analog signal. D4–02DA 2-Ch. Analog Output D4–02DA 2-Ch. Analog Output 11–9 D4-02DA 2-Channel Analog Output Analog Data Bits The first twelve bits of each V-memory location represent the analog data in V40501 & V40502 binary format. The remaining four bits MSB LSB are not used and are ignored by the module. 1 1 1 1 1 1 98 76 54 32 1 0 5 4 3 2 1 0 Bit Value Bit Value 01 6 64 – data bits 1 2 7 128 Unused 2 4 8 256 Bits 3 8 9 512 4 16 10 1024 5 32 11 2048 Since the module has 12-bit resolution, the analog signal is made of 4096 counts 12 ranging from 0 – 4095 (2 ). For example, with a 0 to 10V scale, you would send a 0 to get a 0V signal, and 4095 to get a 10V signal. This is equivalent to a binary value of 0000 0000 0000 to 1111 1111 1111, or 000 to FFF hexadecimal. The following diagram shows how this relates to each signal range. 0 – 10V 1 – 5V 4 – 20mA +10V +5V 20mA 1V 4mA 0V 0 4095 0 4095 0 4095 Each count can also be expressed in H� L Resolution� terms of the signal level by using the 4095 equation shown. The following table shows the smallest signal change that H = high limit of the signal range occurs when the digital value is L = low limit of the signal range increased. Signal Range Span Divide By Smallest Change (H – L) 0 to 10V 10V 4095 2.44 mV 1 to 5V 4V 4095 0.98 mV 4 to 20mA 16mA 4095 3.91 �A 11–10 D4-02DA 2-Channel Analog Output Writing the Control Program Update Either As mentioned earlier, you can update either channel or both channels during the Channel same scan. Since the module does not have any channel select bits, you just simply determine the location of the data word and send the data word to the output module whenever you need to update the data. D4–02DA 8pt 8pt 32pt 16pt 16pt 16pt Output Output Output Output Input Input Y0 Y10 Y20 Y60 – – – – Y7 Y17 Y57 Y77 V40500 V40503 V40502 V40501 MSB LSB MSB LSB Unused Data Bits Unused Data Bits Channel 2 Channel 1 Calculating the Your program has to calculate the digital 4095 A� U Digital Value value to send to the analog module. H� L There are many ways to do this, but most all applications are understood more A = Analog value (0 – 4095) easily if you use measurements in U = Engineering units engineering units. This is accomplished H = High limit of the by using the conversion formula shown. engineering unit range You may have to make adjustments to L = Low limit of the engineering the formula depending on the scale you unit range choose for the engineering units. Consider the following example which controls pressure from 0.0 to 99.9 PSI. By using the formula, you can easily determine the digital value that should be sent to the module. The example shows the conversion required to yield 49.4 PSI. Notice the formula uses a multiplier of 10. This is because the decimal portion of 49.4 cannot be loaded, so you adjust the formula to compensate for it. 4095 A� 10U 10(H� L) 4095 A� 494 1000� 0 A� 2023 D4–02DA 2-Ch. Analog Output D4–02DA 2-Ch. Analog Output 11–11 D4-02DA 2-Channel Analog Output Here is how you would write the program to perform the Engineering Unit conversion. This example assumes you have calculated or loaded the engineering unit value and stored it in V3000. Also, you have to perform this for both channels if you’re using different data for each channel. NOTE: The DL405 offers various instructions that allow you to perform math operations using binary, BCD, etc. It is usually easier to perform any math calculations in BCD and then convert the value to binary before you send the data to the module. If you are using binary math, you do not have to include the BIN conversion. X1 When X1 is on, the engineering units (stored in V3000) are loaded LD into the accumulator. This example assumes the numbers are BCD. V3000 Multiply the accumulator by 4095 (to start the conversion). MUL K4095 Divide the accumulator by 1000 (because we used a multiplier of DIV 10, we have to use 1000 instead of 100). K1000 Convert the BCD number to binary. BIN Store the result in V3101. This is the digital value, in binary form, OUT that should be sent to the module. V3101 Sending the Data The following program example shows how to send the digital values to the module. to the Module SP1 Loads the complete data word into the accumulator. This is the LD digital value that will be sent to the module for channel 1. V3101 Channel 1 is mapped to V40501, so this OUT instruction sends the OUT channel 1 data to that address. V40501 Loads the complete data word into the accumulator. This is the LD digital value that will be sent to the module for channel 2. V3102 Channel 2 is mapped to V40502, so this OUT instruction sends the OUT channel 2 data to that address. V40502 11–12 D4-02DA 2-Channel Analog Output Analog and Digital Sometimes it is helpful to be able to quickly convert between the voltage or current Value Conversions signal levels and the digital values. This is especially useful during machine startup or troubleshooting. The following table provides formulas to make this conversion easier. Range If you know the digital value ... If you know the analog signal level ... 0 to 10V 10D 4095 A� D� (A) 4095 10 1 to 5V 4D 4095 A� �1D� (A� 1) 4095 4 4 to 20mA 4095 16D A� � 4 D� (A� 4) 16 4095 For example, if you are using the 0 to 10V 4095 range and you know you need a 6V D� (A) 10 signal level, you would use the following formula to determine the digital value 4095 D� (6) that should be stored in the V-memory 10 location that contains the data. D� (409.5) (6) D� 2457 D4–02DA 2-Ch. Analog Output